Aheavier mass m1 and a lighter mass m2 are 19.0 cm apart and experience a gravitational force of attraction that is 9.20 x 10^-9 n in magnitude. the two masses have a combined value of 5.80 kg. determine the value of each individual mass.

answers:

m2 = 1.05 kg and m1 = 4.75 kg

Explanation:

the gravitational force is given by:

             Fg = Gm1×m2/(r^2)

9.20×10^-9 = [(6.67×10^-11)×(m1×m2)]/[(19×10-2)^2]

    (m1×m2) = 4.98 kg^2

             m1 = 4.98/m2 kg

but we given that:

m1 + m2 = 5.80 kg

4.98/m2 + m2 = 5.80

4.98 + (m2)^2 = 5.80×m2

(m2)^2 - 5.80×m2 + 4.98 = 0

by solving the quadratic equation above:

m2 = 4.75 kg or m2 = 1.05 kg

due to that from the information, m2 has a lighter mass, then m2 = 1.05 kg.

then m1 = 5.80 - 1.05 = 4.75 kg.

momentum of soft ball three times less than baskey ball

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests