Model rocket engines are rated by their thrust force and by the impulse they provide. you can use this information to determine the time interval at which the engines fire. two rocket engines provide the same impulse. the first engine provides 6 n of thrust for 2 s; the second provides 4 n of thrust.
for how long does this second engine fire?

This second engine fires for 3 s

Acceleration is rate of change of velocity.

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let us now tackle the problem!

Given:

thrust of first engine = F₁ = 6 N

elapsed time of first engine = t₁ = 2 s

thrust of second engine = F₂ = 4 N

Asked:

elapsed time of second engine = t₂ = 2 s

Solution:

We will use Newton's Law of Motion to solve this problem as follows:

→ Impulse Formula

Two rocket engines provide the same impulse :

Grade: High School

Subject: Physics

Chapter: Dynamics

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer