Two manned satellites approach one another at a relative velocity of =0.210v=0.210 m/s, intending to dock. the first has a mass of =4.00×103m1=4.00×103 kg and the second a mass of =7.50×103m2=7.50×103 kg. if the two satellites collide elastically rather than dock, what is their final relative velocity?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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