To make ice, a freezer that is a reverse carnot engine extracts 42 kj as heat at -13°c during each cycle, with coefficient of performance 5.9. the room temperature is 30.9°c. how much (a) energy per cycle is delivered as heat to the room and (b) work per cycle is required to run the freezer?

(a) 49.09 kJ

(b) 7.09 kJ

Explanation:

Qc = 42 kJ

Tc = - 13 degree C = - 13 + 273 = 260 K

TH = 30.9 degree C = 30.9 + 273 = 303.9 K

β = 5.9

(a) Let the heat delivered to the room per cycle is QH.

TH / Tc = QH / Qc

303.9 / 260 = QH / 42

QH = 49.09 kJ

(b) Work done per cycle = QH - Qc = 49.09 - 42 = 7.09 kJ

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

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