Acharge is accelerated from rest through a potential difference v and then enters a uniform magnetic field oriented perpendicular to its path. the field deflects the particle into a circular arc of radius r. if the accelerating potential is tripled to 3v, what will be the radius of the circular

Explanation:

Case 1:

= potential difference through which the charge is accelerated = V

= mass of the charge

= magnitude of charge

= speed gained by the charge due to potential difference

Using conservation of energy

Kinetic energy gained = Electric potential energy lost

= magnitude of magnetic field

= Radius of arc

Radius of arc is given as

                               eq-1

Case 2:

= potential difference through which the charge is accelerated = 3V

= mass of the charge

= magnitude of charge

= speed gained by the charge due to potential difference

Using conservation of energy

Kinetic energy gained = Electric potential energy lost

= magnitude of magnetic field

= Radius of arc

Radius of arc is given as

Using eq-1

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xd

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