Atruck tire rotates at an initial angular speed of 21.5 rad/s. the driver steadily accelerates, and after 3.50 s the tire's angular speed is 28.0 rad/s. what is the tire's angular acceleration (in rad/s2) during this time?

Given:

initial angular speed, = 21.5 rad/s

final angular speed, = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

Now, putting the given values in the above formula:

Therefore, angular acceleration is:

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