The position vector of a particle of mass 1.70 kg as a function of time is given by r with arrow = (6.00 î + 5.70 t ĵ), where r with arrow is in meters and t is in seconds. determine the angular momentum of the particle about the origin as a function of time.

The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

Explanation:

Given that,

Mass = 1.70 kg

Position vector

We need to calculate the angular velocity

The velocity is the rate of change of the position of the particle.

We need to calculate the angular momentum of the particle

Using formula of angular momentum

Where, p = mv

Put the value of p into the formula

Substitute the value into the formula

Hence, The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

answer; equivalent to a one(1) horsepower motor;