Arifle with a mass of m1 = 3.4 kg fires a bullet with a mass of 8.3 g (0.0083 kg). the bullet moves with a velocity of 860 m/s after the rifle is fired. what is the momentum of the bullet after the rifle is fired?

P = 7.138 kg m/s

Explanation:

As we know that momentum is the product of mass and velocity

So here we have

m = 0.0083 kg

velocity = 860 m/s

so momentum of the bullet is given as

so the momentum of bullet after it has been shoot from the rifle is given as

P = 7.138 kg m/s

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y