An air-filled pipe is found to have successive harmonics at 435 hz , 725 hz , and 1015 hz . it is unknown whether harmonics below 435 hz and above 1015 hz exist in the pipe. what is the length of the pipe?

L = 1.706 m

Explanation:

Three successive harmonics in the pipe is given as

now if we take the ratio of all frequency

then we have

f1 : f2 : f3 = 435 : 725 : 1015 = 3 : 5 : 7

since the ratio of consecutive frequency is in ratio of odd numbers so this must be 3rd harmonics, 5th harmonics and 7 harmonics

And as per the formula we have

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.