The distance required for a car to come to a stop will vary depending on how fast the car is moving. suppose that a certain car traveling down the road at a speed of 10 m/s can come to a complete stop within a distance of 20 m . assuming the road conditions remain the same, what would be the stopping distance required for the same car if it were moving at speeds of 5 m/s, 20 m/s, or 40 m/s ?

The stopping distance required for the same car at speeds of 5 m/s, 20 m/s, or 40 m/s is 5m, 80m, and 320 m.

We know that according to the third equation of motion,

given to us

speed of the car, u = 10 m/s

Distance, s = 20 m

Substitute the value to find the deceleration,

The stopping distance required for the same car,

A.) speed, u = 5 m/s

B.) speed, u = 20 m/s

C.) speed, u = 40 m/s

Hence, the stopping distance required for the same car at speeds of 5 m/s, 20 m/s, or 40 m/s is 5m, 80m, and 320 m.

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when speed becomes v = 5 m/s

when speed = 20 m/s

when speed = 40 m/s

Explanation:

Initial speed of the car is given as

now we have

stopping distance = 20 m

final speed = 0

now we have

now we have

now we know that

all conditions remains the same

so stopping distance depends on the speed as

now when speed becomes v = 5 m/s

so it is half of the above speed

so the stopping distance becomes 1/4 times

when speed = 20 m/s that is double the given speed

then the stopping distance becomes 4 times

when speed = 40 m/s that is four times the given speed

then the stopping distance becomes 16 times

the answer is 46 mls because when you add the speed per second it increses the speed

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.