Ablock is suspended from a scale and then lowered into a bucket of water. the density of the water is 1 gm/cm3. the initial reading on the scale is 19n and one complete revolution of the scale is a change of 10n. 1) when the block is lowered into the water, the mass of the block:

1.94 kg

Explanation:

we have given density of water = 1 gm/

the initial reading of the scale = 19 N

change in reading of scale =10 N

we have to find the mass of the block when the block is lowered in water

mass of the block when it is lowered in the water is given by

here g is the gravity of acceleration which value is given by 9.8

so the mass of the block =

the force required to move the cart is divided by three or 33.33 n.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft