An ambulance with a siren emitting a whine at 1790 hz overtakes and passes a cyclist pedaling a bike at 2.36 m/s. after being passed, the cyclist hears a frequency of 1780 hz. how fast is the ambulance moving? (take the speed of sound in air to be 343 m/s.)

The speed of the ambulance is 4.30 m/s

Explanation:

Given:

Frequency of the ambulance, f = 1790 Hz

Frequency at the cyclist, f' = 1780 Hz

Speed of the cyclist, v₀ = 2.36 m/s

let the velocity of the ambulance be 'vₓ'

Now,

the Doppler effect is given as:

where, v is the speed of sound

since the ambulance is moving towards the cyclist. thus, the sign will be positive

thus,

on substituting the values, we get

or

vₓ = 4.30 m/s

Hence, the speed of the ambulance is 4.30 m/s

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c) both a and b.