Two titanium spheres approach each other head-on with the same speed and collide elastically. after the collision, one of the spheres, whose mass is 250 g, remains at rest. (a) what is the mass of the other sphere? (b) what is the speed of the two-sphere center of mass if the initial speed of each sphere is 1.8 m/s?

m2  = 83.3 g

Explanation:

by conservation of momentum principle we have

as both sphere has same speed so

from conservation of kinetic energy principle we have

substituting this value in above equation to get m2 value

solving for m2 we  get

m_1 = 250 g

  m2  = 83.3 g

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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