Aboxcar of mass 8700 kg is traveling at 11.0 m/s strikes a second boxcar moving in the same direction at 2.2 m/s. the two stick together and move off with a speed of 4.00 m/s. what is the mass of the second box car? explain your reasoning.

m = 33833.3 kg

Explanation:

let M be the mass of boxcar 1 and V be the velocity of boxcar 1, let m be the mass of boxcar 2 and v be the velocity of boxcar 2.

from conservation of linear momentum:

M×Vi + m×vi = vf(M + m)

M×Vi - M×vf = m×vf - m×vi

    M(Vi - vf) = m(vf - vi)

                m = [M(Vi - vf)]/(vf - vi)

                    = [(8700)(11.0 - 4.00)]/(4.00 - 2.2)

                    = 33833.3 kg

Therefore, the mass of boxcar 2 is 33833.3 .

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr