Acurrent carrying wire of length 37 cm is positioned perpendicular to a uniform magnetic field. if the current is 3.2 a and it is determined that there is a resultant force of 2.5 n on the wire due to the interaction of the current and field, what is the magnetic field strength?

The magnetic field strength is 2.11 T.

Explanation:

It is given that,

Length of the wire, L = 37 cm = 0.37 m

Current, I = 3.2 A

Force, F = 2.5 N

Magnetic force is given by :

Here,

We know that,

Velocity,

Since,

B = 2.11 T

So, the magnetic field strength is 2.11 T. Hence, this is the required solution.

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.