Plz plz really need steps for this answer
a man standing near a well throws a stone upwards with a velocity of 15ms^-1
find the time the stone takes to reach the bottom of the well which is 15m deep. explain the reason to get 2
plz me : )

3.9 seconds

Explanation:

Use constant acceleration equation:

y = y₀ + v₀ t + ½ at²

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 15 m

v₀ = 15 m/s

a = -9.8 m/s²

Substituting values:

0 = 15 + 15t + ½ (-9.8) t²

0 = 15 + 15t − 4.9t²

0 = 4.9t² − 15t − 15

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 15 ± √((-15)² − 4(4.9)(-15)) ] / 2(4.9)

t = [ 15 ± √(225 + 294) ] / 9.8

t = (15 ± √519) / 9.8

t = -0.79 or 3.9

It takes 3.9 seconds for the stone to reach the bottom of the well.

The negative answer is the time it takes the stone to travel from the bottom of the well up to the top of the well.

3.9 seconds

Explanation:

A man standing near a well throws a stone upwards with a velocity of 15ms^-1. The time the stone takes to reach the bottom of the well, which is 15m deep is  3.9 seconds.

y = y₀ + v₀ t + 1/2 at²

he made 11 calls in one day

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