Two lightweight rods 24 cm in length are mounted perpendicular to an axle and at 180 ∘ to each other. at the end of each rod is a 480-g mass. the rods are spaced 42 cm apart along the axle. the axle rotates at 5.0 rad/s. (a) what is the component of the total angular momentum along the axle? (b) what angle does the vector angular momentum make with the axle? [hint: remember that the vector angular momentum must be calculated about the same point for both masses, which could be the cm.]

Explanation:

Angular momentum ( L ) = moment of inertia x angular velocity ( I X ω )

Moment of inertia of two  480 g masses about axle = 2 x mr²  = 2 x 480 x10⁻³ x( 24 x 10 ⁻ 2 )²  = 0. 552960  kg m².

Angular velocity = 5 rad / s.

Angular momentum = 0.552960 x 5 = 2.765 kg m2.

The direction of angular momentum will be along axle.So vector angular

momentum  makes zero degree  with axle.

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

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