Astrip of copper 190 µm thick and 4.20 mm wide is placed in a uniform magnetic field of magnitude b = 0.78 t, that is perpendicular to the strip. a current i = 32 a is then sent through the strip such that a hall potential difference v appears across the width. calculate v.

V = 9.682 × 10^(-6) V

Explanation:

Given data

thick = 190 µm

wide = 4.20 mm

magnitude B = 0.78 T

current  i = 32 A

to find out

Calculate V

solution

we know v formula that is

V = magnitude× current / (no of charge carriers ×thickness × e

here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³

so put all value we get

V = magnitude× current / (no of charge carriers ×thickness × e

V = 0.78 × 32 / (8.47 x 10^28  × 190 × 1.602 x 10^(-19)

V = 9.682 × 10^(-6) V

terd muffin is the correct answer

what is the actual question though?