Aluge and its rider, with a total mass of 50 kg, emerge from a downhill track onto a horizontal straight track with an initial speed of 30 m/s. if a force slows them to a stop at a constant rate of 4.1 m/s2, (a) what magnitude f is required for the force, (b) what distance d do they travel while slowing, and (c) what work w is done on them by the force? what are (d) f, (e) d, and (f) w if they, instead, slow at 8.2 m/s2?

Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Explanation:

Part a)

Mass of the rider = 50 kg

rate of deceleration of the object = 4.1 m/s/s

now we know by Newton's II law

F = m a

we have

Part b)

Since the rider is decelerated then let say it will be stopped after moving distance "d"

then we have

Part c)

Work done to stop the rider

Part d)

Mass of the rider = 50 kg

rate of deceleration of the object = 8.2 m/s/s

now we know by Newton's II law

F = m a

we have

Part e)

Since the rider is decelerated then let say it will be stopped after moving distance "d"

then we have

Part f)

Work done to stop the rider

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

i think its c if i'm wrong