Physics, 07.08.2019 20:20 antonypaz6583

The speed of light in a vacuum is exactly 299,792,458 m/s. this speed is sometimes used to provide a convenient yardstick for large astronomical distances.(c) a light-year is the distance light travels in one year. the sun is 28,000 light-years from the center of the milky way galaxy. what is this distance in meters?

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Answer from: Tayler9353

$\\2.647191386*10^{20}m$

Explanation:

To answer this question it is necessary to understand that Light travels in vacuum at a constant speed, which means an important property to estimate distances in Universe. We already know that speed of light in vacuum is exactly 299,792,458 m/s.

To solve this question, we need to answer these two ones:

What is the distance that light travels in one year?How many seconds are there in a year?

In the first question, we need to know the distance that light travels in one year, which give us some clue to respond the distance that light travels in 28,000 light-years.

The answer to the second question it is crucial to answer the first question in meters.

How many seconds are there in a year?

$\\ 1year = 365 days * \frac{24h}{day}*\frac{60min}{h}*\frac{60s}{min}=31,536,000s$ .

That is, there are 31,536,000 seconds in a year.

What is the distance that light travels in one year?

Because light travels at a constant speed, the distance can be calculated as follows:

$\\ Speed = \frac{distance}{time}$

or, equivalently,

$\\ distance = Speed * time$

So,

$\\ distance = 299792458\frac{m}{s} * 31536000s$

But, we can see that these are big numbers, and a better way to deal with this is to use scientific notation or floating-point numbers.

Then,

$\\ 299792458\frac{m}{s} = 2.99792458 * 10^{8}\frac{m}{s}$

and,

$\\ 31536000s = 3.1536000*10^{7}s$

So,

$\\ 2.99792458 * 3.1536000 = 9.45425495$ , and,

$\\ 10^{8}*10^{7} = 10^{8 + 7} = 10^{15}$

Then, the total distance that light travels in a year is:

$\\ 9.45425495 * 10^{15}m$

But we now that The Sun is 28,000 light-year from the center of the Milky Way galaxy, and that 28000light-year= $\\2.8 *10^{4}$ light-year.

So, the distance in meters of The Sun from the center of the Milky Way galaxy is:

$\\9.45425495 * 10^{15}m * 2.8 *10^{4}light-year =26.47191386*10^{15}*10^{4}=26.47191386*10^{15+4}=26.47191386*10^{19}=2.647191386*10^{20}m$

Then, the answer is:

$\\2.647191386*10^{20}m$ .

Likewise, the answer could be found as a matter of proportions, mostly because light travels the same distance at each time:

If light travels $\\ 9.45425495 * 10^{15}m$ in a light-year, how many meters does light travel in 28,000 light-year?

$\frac{9.45425495* 10^{15}m}{light-year}$ = $\frac{X meters}{2.8*10^{4}light -year}$ . or

$\\ X =\frac{9.45425495* 10^{15}m}{light-year} * {2.8*10^{4}light -year}=2.647191386*10^{20}m$

That is, the same result.

Notice that we calculate the result using 1 year = 365days. We can add more precision to our answer if we consider 1 year = 365,25days, following the same steps.

Answer from: Quest

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

Answer from: Quest

tdhnjgrgf

explanation:

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The speed of light in a vacuum is exactly 299,792,458 m/s. this speed is sometimes used to provide a...