You arrange to meet a friend at 5: 00 p. m. on valentine’s day on the observation deck of the empire state building in new york city. you arrive right on time, but your friend is not there. she arrives 5 minutes late and says the reason is that time runs faster at the top of a tall building, so she is on time but you were early. is your friend right? does time run slower or faster at the top of a building, as compared with its base? is this a reasonable excuse for your friend arriving 5 minutes late?

double the distance = divide strength by 4

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.