Acar moving at a steady 10 m/s on a level highway encounters a bump that has a circular cross-section with a radius of 30 m. the car maintains its speed over the bump. what is the normal force exerted by the seat of the car on a 60 kg passenger when the car is at the top of the bump? part b) what speed does the car lose contact with the bump road?

(a) Normal force will be 388 N

(B) Speed of the car will be 17.94 m /sec

Explanation:

We have given velocity of the car v = 10 m /sec

radius of the bump = 30 m

Mass of the passenger m = 60 kg

(a) When the car is at the top of the bump then normal force will be equal to weight of the body minus centripetal force

So normal force

(B) When car loose the contact then normal force will be zero

So

v = 17.94 m/sec

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards