A9.50-ω resistor, 8.50-mh inductor, and 90.0-µf capacitor are connected in series to a 45.0-v (rms) source having variable frequency. if the operating frequency is twice the resonance frequency, find the energy delivered to the circuit during one period.

The energy delivered to the circuit during one period is 177.87 mJ.

Explanation:

Given that,

Resistance

Inductance L=8.50 mH

Capacitance

Voltage

We need to calculate the resonance frequency

Using formula of resonance frequency

We need to calculate the period

We need to calculate the inductive resistance

Using formula of inductive resistance

We need to calculate the capacitive resistance

Using formula of capacitive resistance

We need to calculate the impedance

Using formula of impedance

We need to calculate the angle

We need to calculate the energy

Using formula of energy

Put the value into the formula

Hence, The energy delivered to the circuit during one period is 177.87 mJ.

0.863333

86%

hope this

the part of the wave he is travelling on is the crest