A2 kg object released from rest at the top of a tall cliff reaches a terminal speed of 37.5 m/s after it has fallen a height of 110 m . how much kinetic energy approximately did the air molecules gain from the falling object after it has fallen through this height?

3562.25 J

Explanation:

m = mass of the object = 2 kg

v = speed of the object after falling through height of 110 m , = 37.5 m/s

h = height through which the object fall = 110 m

KE = Kinetic energy gained by air molecules

Kinetic energy gained by air molecules is given as

KE = (0.5) m v² + mgh

KE = (0.5) (2) (37.5)² + (2) (9.8) (110)

KE = 3562.25 J

before we can answer, we have to see the choices that are printed there with the question.   that's the only way we can point you to the correct one.

probably not if net force is zero