At a particular point in orbit a satellite in an elliptical orbit h as a gravitational potential energy of 5000mj with respect to earth’s surface and a kinetic energy of 4500mj. later in its orbit, the satellite’s potential energy is 6000mj. what is its kinetic energy at that point?

kinetic energy at that point is 3500 MJ

Explanation:

Given data

potential energy = 5000 MJ

kinetic energy = 4500 MJ

satellite’s potential energy is 6000 MJ

to find out

kinetic energy

solution

we know that total energy is sum of kinetic energy and  potential energy

so kinetic energy will be

kinetic energy = total energy - potential energy     1

here

total energy  = 5000 +  4500 = 9500 MJ

so  now put all value in equation 1

kinetic energy = total energy - potential energy  

kinetic energy = 9500 - 6000 = 3500

so  kinetic energy at that point is 3500 MJ

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.