Aresearch submarine has a 30-cm-diameter window that is 8.1 cm thick. the manufacturer says the window can withstand forces up to 1.1×106 n . part a part complete what is the submarine's maximum safe depth in sea water? the pressure inside the submarine is maintained at 1.0 atm. express your answer in meters.

The pressure at a certain depth underwater is:

P = ρgh

P = pressure, ρ = sea water density, g = gravitational acceleration near Earth, h = depth

The pressure exerted on the submarine window is:

P = F/A

P = pressure, F = force, A = area

The area of the circular submarine window is:

A = π(d/2)²

A = area, d = diameter

Set the expressions for the pressure equal to each other:

F/A = ρgh

Substitute A:

F/(π(d/2)²) = ρgh

Isolate h:

h = F/(ρgπ(d/2)²)

Given values:

F = 1.1×10⁶N

ρ = 1030kg/m³ (pulled from a Google search)

g = 9.81m/s²

d = 30×10⁻²m

Plug in and solve for h:

h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)

h = 1540m

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

v=ir = 3x15 =45 v