A24.0@mf capacitor is charged by a 170.0-v power supply, then disconnected from the power and connected in series with a 0.210-mh inductor. calculate: (a) the oscillation frequency of the circuit; (b) the energy stored in the capacitor at time t = 0 ms (the moment of connection with the inductor); (c) the energy stored in the inductor at t = 1.35 ms.

Part a)

Part b)

U = 111 J

Explanation:

As we know that the capacitor is of capacitance

now the maximum charge on it

Part a)

Oscillation frequency of the charge is given as

Part b)

Now the equation of charge oscillation is given as

now current in the circuit is given as

now at t = 1.35 ms we have

So the energy stored in inductor is given as

multiply 2kg by latent heat of vap

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.