Atoy of mass 0.155 kg is undergoing simple harmonic motion (shm) on the end of a horizontal spring with force constant 305 n/m . when the object is a distance 1.25×10−2 m from its equilibrium position, it is observed to have a speed of 0.305 m/s . part a what is the total energy of the object at any point of its motion

Explanation:

We have given mass m=0.155 kg

Force constant K = 305 N/m

Distance

Velocity

The total energy at any position of the motion is give by  here is energy due to motion and  is energy due to spring elongation

So total energy

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6