Aglass plate (n = 1.64) is covered with a thin, uniform layer of oil (n = 1.27). a light beam of variable wavelength from air is incident normally on the oil surface. observation of the reflected beam shows constructive interference at 501 nm. determine the minimum non-zero thickness of the oil film.

152.7 nm

Explanation:

Refractive index of glass plate = n = 1.64

Refractive index of oil = n' = 1.27

wavelength = λ = 501 nm = 501 e-9 m

2n t = m  λ , since it undergoes constructive interference.

Thickness = t =  501 × 10⁻⁹ m / 2 (1.64)

                      = 152.7 nm

ya te mando la respuesta

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank