Based on what you've learned about heat energy, explain the factors that would determine how quickly a piece of meat cooked on a barbecue grill. why would the amount of water in the meat affect the speed of cooking?

Answer and Explanation:

Heat is a form of energy. It is the total energy of a system associated to the the movement of its molecules or molecular motion.

It depends on various factors like enthalpy of the system, its pressure, temperature, etc.

In the case mentioned, the pace at which meat is cooked on a barbecue grill depends on the water content of the meat and the barbecue grill temperature.

The reason for the cooking speed being affected by amount of water in the is that meat heat energy required to remove the excess water for the proper cooking depends on the water content which if removed completely will result in uncooked meat.

The more the water content the more is the energy requirement to remove it.

Explanation:

Water has a very high specific heat capacity of about 4.186 J/C. This means that the more water that a piece of meat holds, the longer is takes to cook since the water requires more energy to remove from the meat.

The speed of cooking also depends on factors such as the thickness of the meat and the temperature of the grill. The thicker a piece of meat is, the longer it takes for the entire piece of meat to heat completely through. The higher the temperature of the grill, the quicker the heat energy spread throughout the meat.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂