The third-order bright fringe of 610-nm light is observed at an angle of 31° when the light falls on two narrow slits. how far apart are the slits?

The distance between the slits is 3.55 μm

Explanation:

Given that,

Order number = 3

Wave length = 610 nm

Angle = 31°

We need to calculate the distance between the slits

Using formula of distance of slit

Where, n = order number

= wavelength

Put the value into the formula

Hence, The distance between the slits is 3.55 μm.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach