Amichelson interferometer uses light with a wavelength of 452.446 nm. mirror m2 is slowly moved a distance x, causing exactly 2.2700×102 bright-dark-bright fringe shifts to be observed starting and ending with a central bright spot. if the mirror moved only half the distance, what would the final image be?
a. bright spot.
b. dark spot.
c. in between bright and dark spots.
d. impossible to determine, more information needed.

Option b. Dark spot

Explanation:

Michelson interferometer gives the path difference of the light as path difference, d as twice the distance moved or covered by the mirror , x and is given as:

d= 2x

Since, its an even multiple, we obtain a bright fringe

now, when the move half the distance, i.e.,

Therefore, the path difference for half the distance is:

d = x

As it is clear that its an odd multiple which correspond to dark spot as the final image

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete