Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°c 50c water. (c = .5 for ice, c 1 for water, latent heat from ice to water 80 cal/g)

The amount of heat needed is 29000 Cal.

Explanation:

The process involved in this problem are:

Now, we calculate the amount of heat released or absorbed in all the processes.

where,

= amount of heat absorbed = ?

m = mass of ice = 200 g

= final temperature =

= initial temperature =

Putting all the values in above equation, we get:

where,

= amount of heat absorbed = ?

m = mass of water or ice = 200 g

= latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

where,

= amount of heat absorbed = ?

m = mass of water = 200 g

= final temperature =

= initial temperature =

Putting all the values in above equation, we get:

Calculating the total heat absorbed, we get:

Hence, the amount of heat needed is 29000 Cal.

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