Ahorse on a moving train neighed at the fo range at 493 hz with higher harmonics. another stationary horse on the ground heard the whinny as 1433 hz in the go range. find the train moving direction, going away from or coming nearer to the stationary horse? find the train speed. give reasons 443w2 an bns 6mite

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.