Awheel with a weight of 396 n comes off a moving truck and rolls without slipping along a highway. at the bottom of a hill it is rotating at an angular velocity of 22.7 rad/s. the radius of the wheel is 0.569 m and its moment of inertia about its rotation axis is 0.800 mr^2 . friction does work on the wheel as it rolls up the hill to a stop, at a height of above the bottom of the hill; this work has a magnitude of 3476 j . calculate "h" use 9.81 for the acceleration due to gravity.

The height is 5.67 m.

Explanation:

Given that,

Weight = 396 N

Angular velocity = 22.7 rad/s

Radius = 0.569 m

Moment of inertia = 0.800 kg-m²

Work = 3476 J

We need to calculate the kinetic energy

Using formula of kinetic energy

Put the value into the formula

We need to calculate the renaming energy

We need to calculate the height

Using formula of potential energy

Put the value into the formula

Hence, The height is 5.67 m.

probably not if net force is zero

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s