For the circuit shown, r = 75.0 ohms, l= 55.0 mg, and c = 25.0 μc. the power source has 12.0 v arms and a frequency of 60.0 hz. a. what is the value of xl
b. what is the value of xc
c. what is the value of z
d. what is the rms current
e. what is the rms voltage across the resistor
f. what is the rms voltage across the inductors
g. what is the rms voltage across the capacitorh h. how much power is dissipated by the circuit

Explanation:

Given that,

Resistance R = 75.0 ohms

Inductance L = 55.0 mH

Capacitance

Voltage V = 12.0 V

Frequency f = 60.0 Hz

We need to calculate the angular frequency

Using formula of angular frequency

Put the value into the formula

(a). We need to calculate the  value of

Using formula of

Put the value into the formula

(b). We need to calculate the  value of

Using formula of

(c). We need to calculate the value of Z

Using formula of impedance

Put the value into the formula

(d). We need to calculate the rms current

Firstly we need to calculate the current

Using formula of current

Put the value into the formula

Using formula of rms current

(e). We need to calculate the rms voltage across the resistor

Using formula of rms voltage

(f). We need to calculate the rms voltage across the inductor

Using formula of rms voltage

(g). We need to calculate the rms voltage across the capacitor

Using formula of rms voltage

(h).  We need to calculate the dissipated power by the circuit

Using formula of dissipated power

Put the value into the formula

Hence, This is the required solution.

increases it

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is