Ahydrogen atom that is initially at rest absorbs a photon with an energy of 22 ev. what is the momentum of the atom after it absorbs the photon?

1.173 x 10^-26 kg m /s

Explanation:

E = 22 eV

Energy of photon

E = p x c

Where, p is the momentum and c be the velocity of light in vacuum

p = E / c = (22 x 1.6 x 10^-19) / ( 3 x 10^8)

p = 1.173 x 10^-26 kg m /s

1 the 4 is sig

wavelength divides in half and speed stays the same.