Two drops of mercury each has a charge on 0.18 nc and a voltage of 434.21 v. if the two drops are merged into one drop, what is the voltage on this drop?

Explanation:

charge on the drop is given as

V = 434.21 Volts

now we know that

so we have

now when two such drops is merged and forms a single drop then in that case

so we have

now after merging two drops we have total charge on both drops is

now potential of two drops is given as

b.

hope this : )

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.