An x-ray scattering from a free electron is observed to change its wavelength by 3.14pm. at what angle to the incident direction does the scattered x-ray move?

angle to the incident  is 107.09°

Explanation:

Given data

wavelength = 3.14pm = 3.14 × m

to find out

at what  angle to the incident direction scattered

solution

we know that mass of electron that is 9.11 × kg

and velocity of light is 3 × m/s

and h will be 6.63 × J-s

so angle will be calculate by formula that is

wavelength = h ( 1- cosθ )  / (mass of electron × velocity of light )

put here all value

3.14 ×  = 6.63 × ( 1- cosθ) / ( 9.11 × × 3 ×  )

cosθ = 1 - 1.294

cosθ = -0.294

θ = 107.09°

so  angle to the incident  is 107.09°

pe = weightxheight = 2000x1000=2,000,000joules

a skateboard rolling across the street - apex