Araindrop of mass 0.5 * 10^-4 kg is falling verctically under the influence of gravity. the air drag on the raindrop is fdrag = 0.2 * 10^-5 v^2, where v is the speed of the raindrop. find the displacement of the ain drop after 3 second, assume the raindrops starts from rest and use 10m/s^2 for the acceleration of gravity

The displacement of the air drop after 3 second is 18.27 m.

Explanation:

Mass of the rain drop = m =

Weight of the rain drop = W

Duration of time = t = 3 seconds

Drag force on rain drop =

Motion of the rain drop:

Net force on the rain drop , F=  W - D

v = 12.18 m/s

Initial velocity of the rain drop = u = 0 (since, it is starting from rest)

v=u+at (First equation of motion)

(second equation of motion)

s = 18.27 m

The displacement of the air drop after 3 second is 18.27 m.

0.55x745.7j and a calculator

the total distance traveled by the car is

30km + 49km = 79 km .