If 200 cm^3 of tea at 95 degrees celsius is poured into a 150g glass cup initially at 25 degrees celsius, what will be the common final temperature t of the tea and cup when equilibrium is reached, assuming no heat flows to the surroundings?

The final temperature is 85.86°C.

Explanation:

Given that,

Mass of tea = 200 g

Mass of glass = 150 g

Initial temperature = 25°C

We need to calculate the final temperature

When equilibrium is reached, assuming no heat flows to the surroundings

So,

We know that,

Specific heat of tea = 1.00 cal/gm° C

Specific heat of tea = 0.20 cal/gm° C

Put the value into the formula

Put the value of initial temperature

Hence, The final temperature is 85.86°C.

c)as speed changes, wavelength and frequency change.

everything changes!

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever