Alight elastic string, of natural length / and modulus 6 mg, has one end attached to a fixed point o, and to the other end is attached a particle p of mass m. the particle is held at rest at a point a vertically below 0, where 04 = 31/2, and is then released. by energy considerations, or otherwise, show that p is next at rest when it is at a distance 31/4 below 0. show that if the length of the string is i at time i after relcase and before the string becomes slack, then where wa = 6g/l. by making the substitution 1 = y + 1/6, or otherwise, show that the string first becomes slack when 1 271(30).

vapour or gas assuming atmospheriv pressure

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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