An electron moving perpendicular to a uniform magnetic field of 3.2 × 10-2 t moves in a circle of radius 0.40 cm. how fast is this electron moving? (e = 1.60 × 10-19 c, melectron = 9.11 × 10-31kg)

2.25 x 10⁷ m/s

Explanation:

B = magnitude of magnetic field = 0.032 T

r = radius of the circle = 0.40 cm = 0.0040 m

q = magnitude of charge on the electron = 1.60 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of the electron

speed of electron is given as

v = 2.25 x 10⁷ m/s

this is a good question! i'll do some research and come back when i have the answer!