When a light bulb is connected to a 4.5 v battery, a current of 0.12 a passes through the bulb filament. what is the resistance of the filament? a) 440 ω b) 28 ω c) 9.3 ω d) 1.4 ω e) 38 ω

Option (E) 38 ohm

Explanation:

Voltage, V = 4.5 V

Current, i = 0.12 A

Let r be the resistance of the filament of the bulb.

By use of Ohm's law

V = i x R

4.5 = 0.12 x R

R = 4.5 /  0.12 = 37.5 Ohm

By rounding off

R = 38 ohm

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