Aperson is on the top of a 60 m tall building. they throw a coin up into the air with a
velocity of 15 m/s. how fast is the coin moving when it has fallen 20 m away underneath
the person? (show all work)

The coin moves 32,015 m/s when it has fallen 20 m away underneath the person

Regular straight motion is the motion of objects on a straight track that has a fixed speed

Formula used

S = distance = m

v = speed = m / s

t = time = seconds

Straight motion changes regularly are the straight motion of objects that have a fixed acceleration

Formula used

V = vo + at

Vt² = vo² + 2as

St = distance on t

vo = initial speed

vt = speed on t

a = acceleration

The vertical downward motion is part of irregularly changing motion where the acceleration is fixed and the magnitude equal to the acceleration due to gravity (a = g)

Someone on top of a building as tall as 60 m throws a coin with speed

15 m/s.

Then the coin speed when it is 20 m below the height of the building (40 m above ground level is (a = g = 10 m/s²)

vt² = vo² + 2as

vt² = 15² + 2.10.40

vt² = 225 + 800

vt² = 1025

vt = 32,015 m/s

The distance of the elevator

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resultant velocity

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the average velocity

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Keywords: vertical motion, gravitational acceleration, buildings, fixed acceleration

The speed of the coin is 31.765 m/s when it falls 20 m below the person

Further Explanation

Initially, the coin is thrown with the speed of 15m/s upwards.

When coming down the coin will have the same speed of 15 m/s in a downward direction.

Therefore, in diagram;

Normally,  

S = distance = m

v = speed = m / s

t = time = seconds

acceleration due to gravity = g = 9.8 m/s²

and in this case;

u = 15 m/s

h = d = 60 m – 20 m = 40 m (this is because, when the coin is 20 m underneath the person it is 40 m above the ground)

V =?  

We know that, V2 = u2 + 2gh

V² = 15² + (2×9.8×40)

= 225 + 784

= 1009

V = √1009

V = 31.765 m/s

NB. Acceleration due to gravity can also be 10 m/s² instead of 9.8 m/s

The speed of the coin is 31.765 m/s when it falls 20 m below the person

Further Explanation

Initially, the coin is thrown with the speed of 15m/s upwards.

When coming down the coin will have the same speed of 15 m/s in a downward direction.

Therefore, in diagram;

Normally,  

S = distance = m

v = speed = m / s

t = time = seconds

acceleration due to gravity = g = 9.8 m/s²

and in this case;

u = 15 m/s

h = d = 60 m – 20 m = 40 m (this is because, when the coin is 20 m underneath the person it is 40 m above the ground)

V =?  

We know that, V2 = u2 + 2gh

V² = 15² + (2×9.8×40)

= 225 + 784

= 1009

V = √1009

V = 31.765 m/s

NB. Acceleration due to gravity can also be 10 m/s² instead of 9.8 m/s

Answer Details:

Subject:physics

Level: high school

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