What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 k? use the equation: -mv2 = nrt
for m, use 0.02000 kg. remember that r = 8.31 j/(mol-k).

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: