An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. determine its age assuming that in living trees the ratio of (14c/12c) atoms is about 1.30×10^-12. note that the half life of carbon-14 is 5700 years and the avogadro number is 6.02×10^23.

The age of living tree is 11104 years.

Explanation:

Given that,

Mass of pure carbon = 100 g

Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

We need to calculate the decay rate

....(I)

Where, N = number of radio active atoms

=half life

We need to calculate the number of radio active atoms

For

Where, =Avogadro number

For

Put the value in the equation (I)

100 g carbon will decay with rate

We need to calculate the total half lives

We need to calculate the age of living tree

Using formula of age

Hence, The age of living tree is 11104 years.

see earlier

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.