A7.3 cm diameter loop of wire is initially oriented so that its plane is perpendicular to a magnetic field of 0.61 t pointing up. during the course of 0.13 s the field is changed to one of 0.28 t pointing down. what is the magnitude of the induced emf in the coil in mv?

induced emf =  28.65 mV

Explanation:

given data

diameter = 7.3 cm

magnetic field = 0.61

time period = 0.13 s

to find out

magnitude of the induced emf

solution

we know radius is diameter / 2

radius = 7.3 / 2

radius = 3.65 m

so induced emf is dπ/dt  = Adb/dt

induced emf =  A × ΔB / Δt

induced emf =  πr² × ΔB / Δt

induced emf =  π (0..65)² × ( 0.61 - (-0.28))  / 0.13

induced emf =  0.0286538 V

so induced emf =  28.65 mV

another example of kinetic energy would be,

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answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

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