When a downward force is applied at a point 0.60 m to the left of a fulcrum, equilibrium is obtained by placing a mass of 10–7 kg at a point 0.40 m to the right of the fulcrum. what is the magnitude of the downward force

force = 6.53×   N

Explanation:

Given data

downward force = 0.60 m

mass m  = kg

distance h = 0.40 m

to find out

magnitude of the downward force

solution

we know here mg is apply 0.4 m away from support and

so applied force is d =  0.6 m from support

so

by balancing torque we can calculate force

that is

force = mass  × g ×  h / d

put here all these value

force =  mass  × g ×  h / d

force =  (  × 9.81 ×  0.4 )  / 0.6

force = 6.53×   N

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.