Awoman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s about an axis through its center. the disk has a mass of 118 kg and a radius of 3.90 m. calculate the magnitude of the total angular momentum of the woman-plus-disk system. (assume that you can treat the woman as a point.)

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity,

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

I = 1688.31 kg-m²

The angular momentum of the system is :

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

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